22y+1+y^2+11=180

Solution for 22y+1+y^2+11=180 equation:

22y+1+y^2+11=180

We move all terms to the left:

22y+1+y^2+11-(180)=0

We add all the numbers together, and all the variables

y^2+22y-168=0

a = 1; b = 22; c = -168;
Δ = b2-4ac
Δ = 222-4·1·(-168)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-34}{2*1}=\frac{-56}{2}
=-28
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+34}{2*1}=\frac{12}{2}
=6
$